Quale versione del fortran utilizzi?
A cura di Giuseppe Ciaburro
Pubblicato il 04/06/2007
Un programma per la ricerca delle radici di un'equazione quadratica nella forma A * X**2 + B * X + C = 0
PROGRAM roots
!
IMPLICIT NONE
! Declare the variables used in this program
REAL :: a ! Coefficient of X**2 term of equation
REAL :: b ! Coefficient of X term of equation
REAL :: c ! Constant term of equation
REAL :: discriminant ! Discriminant of the equation
REAL :: imag_part ! Imaginary part of equation (for complex roots)
REAL :: real_part ! Real part of equation (for complex roots)
REAL :: x1 ! First solution of equation (for real roots)
REAL :: x2 ! First solution of equation (for real roots)
! Prompt the user for the coefficients of the equation
WRITE (*,*) 'This program solves for the roots of a quadratic '
WRITE (*,*) 'equation of the form A * X**2 + B * X + C = 0. '
WRITE (*,*) 'Enter the coefficients A, B, and C:'
READ (*,*) a, b, c
! Echo back coefficients
WRITE (*,*) 'The coefficients A, B, and C are: ', a, b, c
! Calculate discriminant
discriminant = b**2 - 4. * a * c
! Solve for the roots, depending upon the value of the discriminant
IF ( discriminant > 0. ) THEN ! there are two real roots, so...
X1 = ( -b + sqrt(discriminant) ) / ( 2. * a )
X2 = ( -b - sqrt(discriminant) ) / ( 2. * a )
WRITE (*,*) 'This equation has two real roots:'
WRITE (*,*) 'X1 = ', x1
WRITE (*,*) 'X2 = ', x2
ELSE IF ( discriminant == 0. ) THEN ! there is one repeated root, so...
x1 = ( -b ) / ( 2. * a )
WRITE (*,*) 'This equation has two identical real roots:'
WRITE (*,*) 'X1 = X2 = ', x1
ELSE ! there are complex roots, so ...
real_part = ( -b ) / ( 2. * a )
imag_part = sqrt ( abs ( discriminant ) ) / ( 2. * a )
WRITE (*,*) 'This equation has complex roots:'
WRITE (*,*) 'X1 = ', real_part, ' +i ', imag_part
WRITE (*,*) 'X2 = ', real_part, ' -i ', imag_part
END IF
END PROGRAM